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Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
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Question Type: Memory
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Difficulty Level: Easy
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical cells of the same e.m.f. and same internal resistance
- In n-type semiconductor, electrons are majority charge carriers
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- In a common emitter transistor amplifier, the voltage gain is
- An electron is moving in a circular path under the influence of a transverse magnetic
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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