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Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
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Question Type: Memory
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Difficulty Level: Easy
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Topics: Physical World and Measurement
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The valence band and the conductance band of a solid overlap at low temperature
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- The power supplied by a force acting on a particle moving in a straight line
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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