| ⇦ | 
| ⇨ |
Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film from 10cm x 6cm to 10cm x 11cm. The surface tension of the film is
Options
(a) 5 x10⁻² N/m
(b) 3 x10⁻² N/m
(c) 1.5 x10⁻² N/m
(d) 1.2 x10⁻² N/m
Correct Answer:
3 x10⁻² N/m
Explanation:
Surface tension, S = work done/increase in area
As the soap film has two surfaces.
S = (3.0 x 10⁻⁴ J)/[2 x (10 x 11 – 10 x 6 ) x 10⁻⁴ m²]
= 3 x 10⁻² N/m.
Related Questions: - A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply