Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film

Work Of 30x10 Joule Is Required To Be Done In Physics Question

Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film from 10cm x 6cm to 10cm x 11cm. The surface tension of the film is

Options

(a) 5 x10⁻² N/m
(b) 3 x10⁻² N/m
(c) 1.5 x10⁻² N/m
(d) 1.2 x10⁻² N/m

Correct Answer:

3 x10⁻² N/m

Explanation:

Surface tension, S = work done/increase in area
As the soap film has two surfaces.
S = (3.0 x 10⁻⁴ J)/[2 x (10 x 11 – 10 x 6 ) x 10⁻⁴ m²]
= 3 x 10⁻² N/m.

Related Questions:

  1. A gas of monoatomic hydrogen is bombarded with a stream of electrons
  2. The angle of incidence for a ray of light at a refracting surface of a prism is 45⁰.
  3. The electron drift speed is small and the change of the electron is also small
  4. If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
  5. A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car

Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*