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Which one of the following liquid pairs will exhibit a positive deviation from Raoult’s law
Options
(a) n-hexane and n-heptane
(b) Ethanol and chloroform
(c) Phenol and aniline
(d) Chloroform and acetone
Correct Answer:
Ethanol and chloroform
Explanation:
Since attractive forces between ethanol and chloroform will be weaker as compared to ethanol-ethanol and chloroform-chloroform, hence the tendency to escape is more and vapour pressure of solution is higher than the pure components resulting in positive deviation from Raoult’s law.
Related Questions: - When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,
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Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,
- Ethyl iodide when heated with sodium in dry ether gives pure
- How many moles of iodine are liberated when 1 mole of potassium dichromate
- The wrong statement about fullerene is
- Which of the following is a representation of Gay-Lussac’s law
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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