| ⇦ |
| ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to
Options
(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)
Correct Answer:
1 mol of Hcl(g)
Explanation:
1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole
Related Questions: - The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
- Which of the following is broad spectrum drug
- The compressibility factor of an ideal gas is
- If the value of an equilibrium constant for a particular reaction is 1.6 ˣ 10¹²,
- The two electrons in K-subshell will differ in
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
- Which of the following is broad spectrum drug
- The compressibility factor of an ideal gas is
- If the value of an equilibrium constant for a particular reaction is 1.6 ˣ 10¹²,
- The two electrons in K-subshell will differ in
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply