⇦ | ![]() | ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to
Options
(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)
Correct Answer:
1 mol of Hcl(g)
Explanation:
1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole
Related Questions:
- Which of the following statements is not true about alcohols
- Cobalt(III) chloride forms several octahedral complexes with ammonia.
- The use of chemical for treatment of diseases are called as
- In the laboratory, manganese(II) salt is oxidised to permanganate ion in aqueous
- Smallest wavelength occurs for
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply