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When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to
Options
(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)
Correct Answer:
1 mol of Hcl(g)
Explanation:
1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole
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Question Type: Apply
(15)
Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 0.66 kg ball is moving with a speed of 100 m/s. The associated wavelength
- Which of the following carbonyls will have the strongest C – O bond
- The method not used in metallurgy to refine the impure metal is
- Volume of 0.1 M K₂Cr₂O₇ required to oxidize 35 mL of 0.5 M FeSO₄ solution is
- How will you separate a solution (miscible) of benzene + CHCl₃
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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