| ⇦ | 
| ⇨ |
When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be
Options
(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W
Correct Answer:
20 W
Explanation:
In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R
Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R
Power of combination = P
P = V² / Resistance of combination = 60 / 3 R = 20 W
Related Questions: - Rutherford’s ∝ particle experiment showed that the atoms have
- A glass flask weighing 390 g having internal volume 500 cc just floats
- A rod of weight W is supported by two parallel knife edge A and B
- If two soap bubbles of different radii are connected by a tube
- A particle of mass 1 mg has the same wavelength as an electron moving with a velocity
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Rutherford’s ∝ particle experiment showed that the atoms have
- A glass flask weighing 390 g having internal volume 500 cc just floats
- A rod of weight W is supported by two parallel knife edge A and B
- If two soap bubbles of different radii are connected by a tube
- A particle of mass 1 mg has the same wavelength as an electron moving with a velocity
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply