| ⇦ | 
| ⇨ |
When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be
Options
(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W
Correct Answer:
20 W
Explanation:
In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R
Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R
Power of combination = P
P = V² / Resistance of combination = 60 / 3 R = 20 W
Related Questions: - In a circuit, the current lags behind the voltage by a phase difference of π/2.
- The amount of heat energy required to raise the temperature of 1 g of Helium
- A wheel of mass 10 kg has a moment of inertia of 10 kgm² about its own axis
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- The amount of heat energy required to raise the temperature of 1 g of Helium
- A wheel of mass 10 kg has a moment of inertia of 10 kgm² about its own axis
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply