| ⇦ |
| ⇨ |
When the wavelength of sound changes from 1 m to 1.01 m, the number of beats heard are 4. The velocity of sound is
Options
(a) 400 m/s
(b) 300 m/s
(c) 404 m/s
(d) 100 m/s
Correct Answer:
404 m/s
Explanation:
v = ʋλ ⇒ Now, v = ʋ × 1
v = 1.01 × ʋ’ Also ʋ’ = (ʋ – 4)
So, ʋ × 1 = 1.01 × (ʋ – 4)
⇒ 1.01ʋ – ʋ = 1.01 × 4
0.01ʋ = 1.01 × 4
⇒ ʋ = 404 Hz
v = ʋλ
= 404 × 1 = 404 m/s
Related Questions: - When the temperature increases, the viscocity of
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- To draw the maximum current from a combination of cells, how should be the cells
- A transistor is working in common emitter mode. Its amplification factor is 80
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When the temperature increases, the viscocity of
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- To draw the maximum current from a combination of cells, how should be the cells
- A transistor is working in common emitter mode. Its amplification factor is 80
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply