⇦ | ![]() | ⇨ |
When photons of energy hν fall on an aluminium plate (of work function E₀), photoelectrons of maximum kinetic energy K are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be
Options
(a) K + hν
(b) K + E₀
(c) 2K
(d) K
Correct Answer:
K + hν
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- Calculate the focal length of a reading glass of a person, if the distance
- Two identical thin plano-convex glass lenses (refractive index 1.5) each having
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In refraction, light waves are bent on passing from one medium to the second medium
- An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply