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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric field associated with an e.m. wave in vacuum is given by
- Slope of PV and V for an isobaric process will be
- When two identical capacitors are in series, they have 3 μF capacitance
- The purpose of using heavy water in nuclear reactor is
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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