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When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is
Options
(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃
Correct Answer:
1/v = 1/v₁ + 1/v₂ + 1/v₃
Explanation:
Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- A dust packet is dropped from 5th storey of a multi-storeyed building
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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