When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental

When A String Is Divided Into Three Segments Of Length Physics Question

When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is

Options

(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃

Correct Answer:

1/v = 1/v₁ + 1/v₂ + 1/v₃

Explanation:

Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃

Related Questions:

  1. Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
  2. The electric vector vibration of an electromagnetic wave is given by
  3. A steady current of 1.5 amp flows through a copper voltmeter for 10 minutes
  4. An astronomical telescope arranged for normal adjustment has a magnification of 6.
  5. The maximum kinetic energy of emitted electrons in a photoelectric effect

Topics: Waves (80)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*