| ⇦ | 
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions:
- A ray of light is incident at an angle of incidence i, on one face of a prism
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A monoatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically.
- A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply