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When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
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- Two discs of moment of inertia I₁ and I₂ and angular speeds ?￢ﾂﾁ and ?￢ﾂﾂ are rotating
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The physical quantities not having same dimensions are
- Two discs of moment of inertia I₁ and I₂ and angular speeds ?￢ﾂﾁ and ?￢ﾂﾂ are rotating
- Ring, hollow ring and solid sphere are rolled down from inclined plane
- The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas
- If a body is rolling on the surface, its total energy will be
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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