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When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solid cylinder of mass 50kg and radius 0.5 m is, free to rotate about the horizontal axis
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- The resistance of a carbon resistor of colour code Red-Red Green Silver is(in kΩ)
- Depletion layer contains
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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