| ⇦ | 
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- When one of the slits of Young’s experiment is covered with a transport sheet
- In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
- In a parallel plate capacitor of capacitance C, a metal sheet is inserted
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- When one of the slits of Young’s experiment is covered with a transport sheet
- In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
- In a parallel plate capacitor of capacitance C, a metal sheet is inserted
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply