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When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - The displacement of a particle varies according to the relation x=4 (cos π t + sin π t)
- A wire is suspended vertically from one of its ends is stretched by attaching a weight
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The displacement of a particle varies according to the relation x=4 (cos π t + sin π t)
- A wire is suspended vertically from one of its ends is stretched by attaching a weight
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
- A beam of electron passes undeflected through mutually perpendicular
- In the phenomenon of electric discharge through gases at low pressure,
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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