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When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring?
Options
(a) kl/2
(b) 2kl
(c) 1/2 Mgl
(d) Mgl
Correct Answer:
Mgl
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
- The work of 146 kJ is performed in order to compress one kilo mole fo gas adiabatically
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- A coin of mass m and radius r having moment of inertia I about the axis passes
- The minimum wavelength of X-rays emitted by X-ray tube is 0.4125Å
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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initially spring is at rest . when we attach mass of m to it then in order to have maximum amplitude l the spring must have to stretch by a length 2l so maximum potential energy in the spring should be 1/2 k x^2 put x=2l and mg=2lk
FINAL ANSWER IS Mgl
good