| ⇦ | 
| ⇨ |
When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring?
Options
(a) kl/2
(b) 2kl
(c) 1/2 Mgl
(d) Mgl
Correct Answer:
Mgl
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- A monoatomic gas at a pressure P, having a volume V expands isothermally
- A body moves with a uniform acceleration a and zero initial velocity
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- The electron drift speed is small and the change of the electron is also small
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- A monoatomic gas at a pressure P, having a volume V expands isothermally
- A body moves with a uniform acceleration a and zero initial velocity
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- The electron drift speed is small and the change of the electron is also small
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
initially spring is at rest . when we attach mass of m to it then in order to have maximum amplitude l the spring must have to stretch by a length 2l so maximum potential energy in the spring should be 1/2 k x^2 put x=2l and mg=2lk
FINAL ANSWER IS Mgl
good