| ⇦ | 
| ⇨ |
When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring?
Options
(a) kl/2
(b) 2kl
(c) 1/2 Mgl
(d) Mgl
Correct Answer:
Mgl
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A mass m moves in a circle on a smooth horizontal plane with velocity v₀
- A wire mesh consisting of very small squares is viewed at a distance
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- A galvanometer is converted into an ammeter by connecting
- An air core coil and an electric bulb are connected in series with an AC source.
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
- A wire mesh consisting of very small squares is viewed at a distance
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- A galvanometer is converted into an ammeter by connecting
- An air core coil and an electric bulb are connected in series with an AC source.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
initially spring is at rest . when we attach mass of m to it then in order to have maximum amplitude l the spring must have to stretch by a length 2l so maximum potential energy in the spring should be 1/2 k x^2 put x=2l and mg=2lk
FINAL ANSWER IS Mgl
good