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When a current of (2.5±0.5) A flows through a wire, it develops a potential difference of (20±1) V, then the resistance of wire is
Options
(a) (8±2)Ω
(b) (8±1.6)Ω
(c) (8±1.5)Ω
(d) (8±3)Ω
Correct Answer:
(8±2)Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Current Electricity
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Subject: Physics
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- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
- A thin rod of length L and mass M is held vertically with one end on the floor
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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R=V/I
R=20/2.5
R= 8 ohm
Now,
∆ R/R=∆ V/V+∆I/I
=1/20 +0.5/2.5
= 1/4
Therefore,
∆ R÷R=1÷4
∆ R=1÷4×R
∆R=1÷4×8
∆R=2
Therefore,
Resistance with error limits=R+ – ∆R
=(8+ – 2)ohm