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When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to
Options
(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)
Correct Answer:
1 mol of HCl(g)
Explanation:
H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole
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Topics: Some Basic concepts of Chemistry
(5)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What will be the partial pressure of He and O₂, if 200 mL of He at 0.66 atm and 400 mL
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- The rate of reaction between two reactants A and B decreases by a factor of
- A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained
Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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