When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,

⇦

⇨

When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to

Options

(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)

Correct Answer:

1 mol of HCl(g)

Explanation:

H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole

Related Questions:

1. For a spontaneous process, entropy always
2. Portland cement contains the following amount of CaO
3. Which one of the following is a molecular crystal
4. Among the following pairs of ions, the lower oxidation state in aqueous solution
5. Which is a metalloid

Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends