When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,

⇦

⇨

When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to

Options

(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)

Correct Answer:

1 mol of HCl(g)

Explanation:

H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole

Related Questions:

1. The hardness of transition elements is due to their
2. Deuterium nucleus contains
3. The orthophosphoric acid is a
4. In which one of the following molecules the central atom does not have sp³
5. Which of the following statement about water is wrong?

Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends