| ⇦ |
| ⇨ |
The most basic amine among the following is
Options
(a) p-toluidine
(b) o-nitroaniline
(c) p-nitroaniline
(d) 2,4-dinitroaniline
Correct Answer:
p-toluidine
Explanation:
Basicity of amines increases with the presence of electron releasing groups and decreases with the presence of electron withdrawing group. Among the give options, only p-toluidine has aniline with an electron donating -CH₃ group which, by virtue of its +I-effect, increases the electron density on N-atom and makes electrons more available for protonation. In o-nitroaniline, p-nitroaniline and 2,4-dinitroaniline, due to presence of electron withdrawing -NO₂ group, the electron density on N-atom is diminished. Thus, it is less basic. Similarly for p-fluoroaniline.
Related Questions: - The fractional distillation is used in
- Which of the following shows geometrical isomerism
- Which of the following carbonates is the most stable?
- M⁺³ ion loses 3e⁻. Its oxidation number will be
- A liquid is in equilibrium with its vapour at its boiling point
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The fractional distillation is used in
- Which of the following shows geometrical isomerism
- Which of the following carbonates is the most stable?
- M⁺³ ion loses 3e⁻. Its oxidation number will be
- A liquid is in equilibrium with its vapour at its boiling point
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply