| ⇦ |
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - When a mass M is attached to a spring of force constant K,
- In Young’s double silt experiment if the distance between the two slits
- Penetrating power of X-rays does not depend on
- The moment of inertia of a thin uniform rod of mass M and length L about an axis
- A round uniform body of radius R, mass M and moment of inertia I rolls down
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a mass M is attached to a spring of force constant K,
- In Young’s double silt experiment if the distance between the two slits
- Penetrating power of X-rays does not depend on
- The moment of inertia of a thin uniform rod of mass M and length L about an axis
- A round uniform body of radius R, mass M and moment of inertia I rolls down
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply