| ⇦ | 
| ⇨ |
A block of wood weighs 10 N and is resting on an inclined plane. The coefficient of friction is 0.7. The frictional force that acts on the block, when the plane is 30° inclined with the horizontal is
Options
(a) 6.062 N
(b) 5N
(c) 9.8N
(d) 70N
Correct Answer:
5N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- The moment of inertia of a semicircular ring about the centre is
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- The moment of inertia of a semicircular ring about the centre is
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply