| ⇦ | 
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - If a proton, a deuteron and an alpha particle, on being accelerated by the same
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- what is the electric potential at a distance of 9cm from 3nC?
- Fusion reaction takes place at high temperature because
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- what is the electric potential at a distance of 9cm from 3nC?
- Fusion reaction takes place at high temperature because
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply