⇦ | ⇨ |
What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th seconds of journey?
Options
(a) 4 : 5
(b) 7 : 9
(c) 16 : 25
(d) 1 : 1
Correct Answer:
7 : 9
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The oscillating frequency of a cyclotron is 10 MHz. If the radius of its Dees is o.5 m,
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- If the density of earth is doubled keeping its radius constant then acceleration
- The magnetic moment has dimensions of
- A body starts from rest, what is the ratio of the distance travelled by the body
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oscillating frequency of a cyclotron is 10 MHz. If the radius of its Dees is o.5 m,
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- If the density of earth is doubled keeping its radius constant then acceleration
- The magnetic moment has dimensions of
- A body starts from rest, what is the ratio of the distance travelled by the body
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
By using,
Snth=u+a/2 (2n-1)=0+a/2 (2×4-1)=7a/2
Again,s=u+a/2 (2n-1)=0+a/2 (2×5-1)=9a/2
Now,S1:S2=7a/2:9a/2=7:9