| ⇦ |
| ⇨ |
What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω and load resistance is 24 Ω? Take β=0.6
Options
(a) 3.6
(b) 4.8
(c) 2.4
(d) 1.2
Correct Answer:
3.6
Explanation:
Input resistance Rᵢ = 4Ω
Load resistance Rʟ = 24Ω
Resistance gain = Rʟ / Rᵢ = 24Ω / 4Ω = 6
Current gain β = 0.6
Voltage gain = Current gain x Resistance gain
= 0.6 x 6 = 3.6
Related Questions: - If a body is rolling on the surface, its total energy will be
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- The ratio of specific charge of an α-particle to that of a proton is
- In a circuit, L,C and R are connected in series with an alternating voltage source
- Energy of all molecules of a monoatomic gas having a volume V and pressure P is 3PV/2.
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a body is rolling on the surface, its total energy will be
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- The ratio of specific charge of an α-particle to that of a proton is
- In a circuit, L,C and R are connected in series with an alternating voltage source
- Energy of all molecules of a monoatomic gas having a volume V and pressure P is 3PV/2.
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply