| ⇦ |
| ⇨ |
What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions: - Which of the following is an ore of aluminium
- The ability of a given substance to assume two or more crystalline structure is
- The class of drugs used for the treatment of stress is
- The oxidation state of Fe in brown ring complex [Fe(H₂O)₅NO]SO₄ is
- In the softening of the water by passing it through cationic and anionic exchang
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is an ore of aluminium
- The ability of a given substance to assume two or more crystalline structure is
- The class of drugs used for the treatment of stress is
- The oxidation state of Fe in brown ring complex [Fe(H₂O)₅NO]SO₄ is
- In the softening of the water by passing it through cationic and anionic exchang
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply