| ⇦ | 
| ⇨ |
What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions: - The complex [Co(NH₃)₅Br]²⁺ SO₄²⁻ and [Co(NH₃)₅SO₄]⁺ Br⁻ are
- A sample of chloroform before being used as an anaesthetic agent is tested by
- Nitrobenzene combines with hydrogen in the presence of platinum to yield
- Solubility of iodine in water may be increased by adding
- Which of the following acts as both reducing and oxidising agent
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The complex [Co(NH₃)₅Br]²⁺ SO₄²⁻ and [Co(NH₃)₅SO₄]⁺ Br⁻ are
- A sample of chloroform before being used as an anaesthetic agent is tested by
- Nitrobenzene combines with hydrogen in the presence of platinum to yield
- Solubility of iodine in water may be increased by adding
- Which of the following acts as both reducing and oxidising agent
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply