What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl

What Is The Oh In The Final Solution Prepared By Chemistry Question

What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl with 30 mL of 0.1 M Ba(OH)₂?

Options

(a) 0.4 M
(b) 0.005 M
(c) 0.12 M
(d) 0.1 M

Correct Answer:

0.1 M

Explanation:

No of milliequivalent of HCl = 20 x 0.05 =1.0
No of milliequivalent of Br(OH)₂ = 30 x 0.1 x 2 = 60
after neutralization, no of milliequivalents in 50 ml of solution = 6-1=5
Total vol of solution = 20 + 30 = 50 ml
No of milliequivalent of OH⁻ is 5 in 50 ml
[OH⁻] = (5 x 100 / 10 ) x 10⁻³ = 0.1 M

Related Questions:

  1. Which one of the following has an aromatic character
  2. Which of the following is an ore of aluminium
  3. At higher temperature,iodoform reaction is given by
  4. Which of the following is heavy water
  5. If concentration of reactants is increased by ‘x’,then the K becomes

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*