| ⇦ | 
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - The basic component of the smog is
- Oxidation state of iron in [Fe(H₂O)₅NO]SO₄ is
- The plot of concentration of the reactant vs time for a reaction is a straight
- Acetyl salicylic acid is used as
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The basic component of the smog is
- Oxidation state of iron in [Fe(H₂O)₅NO]SO₄ is
- The plot of concentration of the reactant vs time for a reaction is a straight
- Acetyl salicylic acid is used as
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply