| ⇦ |
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - Ethyne can be oxidised to oxalic acid by using
- Gram molecular volume of oxygen at STP is
- 100 cm of a given sample of H₂O₂ gives 1000 cm³ of O₂ at STP. The given sample is
- Which reagent can be used for the alkylation of aromatic nitro compounds
- The pH value of a 10 M solution of HCl is
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethyne can be oxidised to oxalic acid by using
- Gram molecular volume of oxygen at STP is
- 100 cm of a given sample of H₂O₂ gives 1000 cm³ of O₂ at STP. The given sample is
- Which reagent can be used for the alkylation of aromatic nitro compounds
- The pH value of a 10 M solution of HCl is
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply