| ⇦ |
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - Electric field at a point of distance r from a uniformly charged wire of infinite
- When a metallic surface is illuminated with radiation of wavelength λ,
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
- The number of photo electrons emitted for light of a frequency v
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electric field at a point of distance r from a uniformly charged wire of infinite
- When a metallic surface is illuminated with radiation of wavelength λ,
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
- The number of photo electrons emitted for light of a frequency v
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply