| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - A planet moving along an elliptical orbit is closest to the sun at a distance of r₁
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
- The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
- In Bohr model of hydrogen atom, the force on the electron depends on the principal
- The transverse nature of electromagnetic waves is proved by which of the following?
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A planet moving along an elliptical orbit is closest to the sun at a distance of r₁
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
- The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
- In Bohr model of hydrogen atom, the force on the electron depends on the principal
- The transverse nature of electromagnetic waves is proved by which of the following?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply