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A particle under the action of a constant force moves from rest upto 20 seconds. If distance covered in first 10 seconds is S₁ and that covered in next seconds is S₂, then
Options
(a) S₁ = S₂
(b) S₂ = 3S₁
(c) S₂ = 2S₁
(d) S₂ = 4S₁
Correct Answer:
S₂ = 3S₁
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- Which component of electromagnetic spectrum have maximum wavelength?
- A block of mass m is placed on a smooth wedge of inclination θ
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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