| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The unit of permitivity of free space, ε₀ is
- The physical quantity which does not have the same dimensions as the other three is
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- when a magnetic field is applied on a stationary electron, then it
- The width of the diffraction band varies
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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