⇦ | ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- The most important characteristic of electron in the production of X-rays is
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- When a mass m is attached to a spring, it normally extends by 0.2 m.
- The process of adding impurities to the pure semiconductor is called
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- The most important characteristic of electron in the production of X-rays is
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- When a mass m is attached to a spring, it normally extends by 0.2 m.
- The process of adding impurities to the pure semiconductor is called
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply