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| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - The primary and secondary coil of the transformer have 50 and 1500 turns respectively
- When 4 A current flows for 2 min in an electroplating experiment,
- A source of light is placed at a distance of 50 cm from a photocell and the stopping
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The primary and secondary coil of the transformer have 50 and 1500 turns respectively
- When 4 A current flows for 2 min in an electroplating experiment,
- A source of light is placed at a distance of 50 cm from a photocell and the stopping
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- The period of a simple pendulum inside a stationary lift is T. The lift accelerates
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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