| ⇦ | 
| ⇨ |
Volume occupied by one molecule of water (density= 1 g cm⁻³) is
Options
(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³
Correct Answer:
3 x 10⁻²³ cm³
Explanation:
density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³
Related Questions: - Of the following, which change will shift the reaction towards the product
- The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³
- The correct order of electron affinity is
- In alkaline hydrolysis of a tertiary alkyl halides by aqueous alkali,
- The pair of species that has the same bond order in the following is:
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Of the following, which change will shift the reaction towards the product
- The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³
- The correct order of electron affinity is
- In alkaline hydrolysis of a tertiary alkyl halides by aqueous alkali,
- The pair of species that has the same bond order in the following is:
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply