| ⇦ | 
| ⇨ |
Volume occupied by one molecule of water (density= 1 g cm⁻³) is
Options
(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³
Correct Answer:
3 x 10⁻²³ cm³
Explanation:
density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³
Related Questions: - Carnallite on electrolysis gives
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
- As the alkaline earth metals (except Be) tend to lose their valence electrons
- The volume of water to be added to 100 cm³ of 0.5 N H₂SO₄ to get decinormal
- Propanone and propanal are …. Isomers
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Carnallite on electrolysis gives
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
- As the alkaline earth metals (except Be) tend to lose their valence electrons
- The volume of water to be added to 100 cm³ of 0.5 N H₂SO₄ to get decinormal
- Propanone and propanal are …. Isomers
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply