Volume occupied by one molecule of water (density= 1 g cm⁻³) is

Volume Occupied By One Molecule Of Water Density 1 G Chemistry Question

Volume occupied by one molecule of water (density= 1 g cm⁻³) is

Options

(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³

Correct Answer:

3 x 10⁻²³ cm³

Explanation:

density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³

Related Questions:

  1. Toluene can be oxidised to benzoic acid by
  2. Benzoic acid with Ba(OH)₂ gives
  3. Using the Gibb’s energy change,ΔG⁰ = +63.3 kJ, for the following reaction
  4. At 27⁰C latent heat of fusion of a compound is 2930 J/mol. Entropy change is
  5. In liquid-gas equilibrium,the pressure of vapours above the liquid is constant

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*