| ⇦ | 
| ⇨ |
Two wires of the same dimensions but resistivities p1 and p2 are connected in series. The equivalent resistivity of the combination is
Options
(a) p1 + p2
(b) (p1 + p2) / 2
(c) √(p1 p2)
(d) 2 (p1 + p2)
Correct Answer:
(p1 + p2) / 2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- What is the energy released by fission of 1 g of U²³⁵?
- The displacement of an object attached to a spring and executing simple harmonic
- In n-type semiconductor, electrons are majority charge carriers
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- What is the energy released by fission of 1 g of U²³⁵?
- The displacement of an object attached to a spring and executing simple harmonic
- In n-type semiconductor, electrons are majority charge carriers
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply