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Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m and y₂ = a cos (?t + kx) m, where x is in meter and t in sec. The phase difference between them is
Options
(a) 1.0 radian
(b) 1.25 radian
(c) 1.57 radian
(d) 0.57 radian
Correct Answer:
1.0 radian
Explanation:
Here, y₁ = a sin (?t + kx + 0.57 )
and y₂ = a cos (?t + kx )
= a sin [π/2 + (?t – kx)
Phase difference, ∆? = ?￢ﾂﾂ – ?￢ﾂﾁ
= π/2 – 0.57 = 3.14 / 2 – 0.57 = 1.57 – 0.57
1 radian
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Topics: Waves
(80)
Subject: Physics
(2479)
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