| ⇦ | 
| ⇨ |
The point of suspension λ of a simple pendulum with normal time period T₁ is moving upward according to equation y=kt² where k=1 m/s². If new time period is T² the ratio T₁²/T₂² will be
Options
(a) (2/3)
(b) (5/6)
(c) (6/5)
(d) (3/2)
Correct Answer:
(6/5)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The relationship between decay constant λ and half-life T of a radioactive substance is
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Three resistances P,Q,R each of 2Ω and an unknown resistances S form the four arms
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
- In common base circuit of a transistor, current amplification factor is 0.95.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The relationship between decay constant λ and half-life T of a radioactive substance is
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Three resistances P,Q,R each of 2Ω and an unknown resistances S form the four arms
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
- In common base circuit of a transistor, current amplification factor is 0.95.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply