The point of suspension λ of a simple pendulum with normal time period T₁ is moving

The Point Of Suspension Of A Simple Pendulum With Physics Question

The point of suspension λ of a simple pendulum with normal time period T₁ is moving upward according to equation y=kt² where k=1 m/s². If new time period is T² the ratio T₁²/T₂² will be

Options

(a) (2/3)
(b) (5/6)
(c) (6/5)
(d) (3/2)

Correct Answer:

(6/5)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. The potential energy of a 1 kg particle free to move along the x-axis is given by
  2. If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
  3. A liquid wets a solid completely. The meniscus of the liquid in a sufficiently long
  4. A speeding motorcyclist sees traffic jam ahead him. He slows down to 36 km per hour
  5. A solid sphere is rotating in free space.If the radius of the sphere is increased

Topics: Oscillations (58)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*