| ⇦ |
| ⇨ |
Two tuning forks are sounded together and produce 2 beats per second. The frequency of one of them is 288 Hz. The other is loaded with some wax and now they produce four beats per sec. The frequency of the other tuning fork is
Options
(a) 284 Hz
(b) 286 Hz
(c) 290 Hz
(d) 292 Hz
Correct Answer:
286 Hz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which series of hydrogen spectrum corresponds to ultraviolet region?
- The input signal given to a CE amplifier having a voltage gain of 150 is
- Wavefront is the locus of all points, where the particles of the medium
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- A round uniform body of radius R, mass M and moment of inertia I rolls down
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which series of hydrogen spectrum corresponds to ultraviolet region?
- The input signal given to a CE amplifier having a voltage gain of 150 is
- Wavefront is the locus of all points, where the particles of the medium
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- A round uniform body of radius R, mass M and moment of inertia I rolls down
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply