⇦ | ![]() | ⇨ |
Two thin long conductors seprated by a distance d carry currents I₁ and I₂ in the same direction. They exert a force F on each other. Now, the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of force between them is
Options
(a) (-2F)
(b) F/3
(c) (-2F/3)
(d) (-F/3)
Correct Answer:
(-2F/3)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- A thin rod of length L and mass M is held vertically with one end on the floor
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply