⇦ | ⇨ |
Two thin lenses of focal lengths f₁ and f₂ are in contact and coaxial. The power of the combination is:
Options
(a) √ f₁ / f₂
(b) √ f₂ / f₁
(c) f₁ + f₂ / 2
(d) f₁ + f₂ / f₁f₂
Correct Answer:
f₁ + f₂ / f₁f₂
Explanation:
The focal length of the combination
1/f = 1/f₁ + 1/f₂
Power of the combinations,
P = f₁ + f₂ / f₁ f₂ ( P = 1 / f )
Related Questions: - A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply