| ⇦ | 
| ⇨ |
Two thin lenses of focal lengths f₁ and f₂ are in contact and coaxial. The power of the combination is:
Options
(a) √ f₁ / f₂
(b) √ f₂ / f₁
(c) f₁ + f₂ / 2
(d) f₁ + f₂ / f₁f₂
Correct Answer:
f₁ + f₂ / f₁f₂
Explanation:
The focal length of the combination
1/f = 1/f₁ + 1/f₂
Power of the combinations,
P = f₁ + f₂ / f₁ f₂ ( P = 1 / f )
Related Questions: - Which dimensions will be the same as that of time?
- A ray of light passes from a medium A having refractive index 1.6 to the medium
- Unit of reduction factor is
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which dimensions will be the same as that of time?
- A ray of light passes from a medium A having refractive index 1.6 to the medium
- Unit of reduction factor is
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply