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Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m are stretched by the same force. The ratio of potential energy stored in springs will be
Options
(a) 1:2
(b) 2:1
(c) 4:1
(d) 1:4
Correct Answer:
2:1
Explanation:
Force F=-Kxdisplacement (x),
Potential Energy = U =(1/2) Kx²
U = (1/2) K(F/K)² = (1/2)(F²/K)
U₁/U₂=(1/2)(F²/K₁)x(2K₂/F²)
K₂/K₁=3000/1500=2/1.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
- A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- An alternating voltage given as, V=100√2 sin100t V is applied to a capacitor
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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