⇦ | ![]() | ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions:
- If wavelength of a wave is λ=6000 Å, then wave number will be
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- A magnetic field of 1600 A/m produces a magnetic flux of 2.4 x 10⁻⁵ Wb
- An A.C source is rated at 220 V, 50 Hz. The time taken for voltage to change
- A body of mass m slides down an incline and reaches the bottom
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2