| ⇦ | 
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
- The distance travelled by an object along a straight line in time t is given by
- The dimensions of magnetic field intensity B are
- In a transistor, the value of βis 100, then the value of α will be
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
- The distance travelled by an object along a straight line in time t is given by
- The dimensions of magnetic field intensity B are
- In a transistor, the value of βis 100, then the value of α will be
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2