| ⇦ |
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- The phase difference between the instantaneous velocity and acceleration of a particle
- Two lenses of power 15 D and -3 D are placed in contact.
- The S.I. unit of electric flux is
- The ratio of magnetic dipole moment of an electron of charge e and mass m
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- The phase difference between the instantaneous velocity and acceleration of a particle
- Two lenses of power 15 D and -3 D are placed in contact.
- The S.I. unit of electric flux is
- The ratio of magnetic dipole moment of an electron of charge e and mass m
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2