| ⇦ | 
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - Which of the following phenomena does not show the wavenature of light?
- If by mistake voltmeter is connected in series and ammeter in parallel then
- In R-L-C series circuit, the potential differences across each element is 20 V.
- A particle A suffers on oblique elastic collision with a particle B that
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following phenomena does not show the wavenature of light?
- If by mistake voltmeter is connected in series and ammeter in parallel then
- In R-L-C series circuit, the potential differences across each element is 20 V.
- A particle A suffers on oblique elastic collision with a particle B that
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2