| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- According to Hook’s law, force is proportional to
- A body of mass m is orbiting the earth at a radius r from the center of earth
- Radiofrequency choke uses core of
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- According to Hook’s law, force is proportional to
- A body of mass m is orbiting the earth at a radius r from the center of earth
- Radiofrequency choke uses core of
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply