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Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be ( e being the charge of an electron)
Options
(a) 4π?￢ﾂﾀFd² / e²
(b) √(4π?￢ﾂﾀFe² / d²)
(c) √(4π?￢ﾂﾀFd² / e²)
(d) 4π?￢ﾂﾀFd² / q²
Correct Answer:
√(4π?￢ﾂﾀFd² / e²)
Explanation:
Let ne be the no. of electrons missing.
F = 1 / 4π?￢ﾂﾀ . q² / d²
q = √(4π?￢ﾂﾀd²F) = ne
n = √(4π?￢ﾂﾀFd² / e²)
Related Questions: - What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- Identify the pair whose dimensions are equal
- A person has a minimum distance of distinct vision as 50 cm. The power of lenses
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- Identify the pair whose dimensions are equal
- A person has a minimum distance of distinct vision as 50 cm. The power of lenses
- Oil spreads over the surface of water where as water does not spread
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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