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Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂ respectively. Then
Options
(a) n₁²d₁²=n₂²d₂²
(b) n₁²d₁³=n₂²d₂³
(c) n₁d₁²=n₂d₂²
(d) n₁²d₁=n₂²d₂
Correct Answer:
n₁²d₁³=n₂²d₂³
Explanation:
Apply Kepler’s third law, T²∞R³
T²/R³=constant
Given: T=1/n and R=d
T²/R³=1/n².1/d³=constant
n²d³=constant
For the two planets,n₁²d₁³=n₂²d₂³
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A disc of mass 100 g is kept floating horizontally in air by firing bullets
- A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- In the relation n=PV/RT, n stands for
- Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
- A radioactive element forms its own isotope after 3 consecutive disintegrations.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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