The horizontal range of a projectile is 4√3 times the maximum height achieved

The Horizontal Range Of A Projectile Is 43 Times The Physics Question

The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is

Options

(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰

Correct Answer:

30⁰

Explanation:

u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°

Related Questions:

  1. An alternating emf given by equation e=300 sin⁡[(100 π)t] V
  2. A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
  3. In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
  4. A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
  5. A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof

Topics: Motion in Plane (93)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*