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The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
Related Questions: - Bragg’s law for X-rays is
- For principal quantum number n=3, the possible values of orbital quantum number
- Zener diode is used
- The number of photo electrons emitted for light of a frequency v
- Two nuclei have their mass numbers into the ratio of 1:3
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bragg’s law for X-rays is
- For principal quantum number n=3, the possible values of orbital quantum number
- Zener diode is used
- The number of photo electrons emitted for light of a frequency v
- Two nuclei have their mass numbers into the ratio of 1:3
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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