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Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂ respectively. Then
Options
(a) n₁²d₁²=n₂²d₂²
(b) n₁²d₁³=n₂²d₂³
(c) n₁d₁²=n₂d₂²
(d) n₁²d₁=n₂²d₂
Correct Answer:
n₁²d₁³=n₂²d₂³
Explanation:
Apply Kepler’s third law, T²∞R³
T²/R³=constant
Given: T=1/n and R=d
T²/R³=1/n².1/d³=constant
n²d³=constant
For the two planets,n₁²d₁³=n₂²d₂³
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tube of length L is filled completely with an incompressible liquid of mass
- The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force
- Two bodies A and B have masses 20 Kg and 5 Kg respectively. Each one is acted
- A particle moves in a circle of radius 5 cm with constant speed and time period
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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